8x^2=2+17x

Solution for 8x^2=2+17x equation:

8x^2=2+17x

We move all terms to the left:

8x^2-(2+17x)=0

We add all the numbers together, and all the variables

8x^2-(17x+2)=0

We get rid of parentheses

8x^2-17x-2=0

a = 8; b = -17; c = -2;
Δ = b2-4ac
Δ = -172-4·8·(-2)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{353}}{2*8}=\frac{17-\sqrt{353}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{353}}{2*8}=\frac{17+\sqrt{353}}{16}
$